Slacky McSlackAss Posted April 3, 2009 Share Posted April 3, 2009 Computer science is the DEBIL! Hours and hours of debugging for a mistake you'll never find. What turned me away from engineering was HORRIBLE Physics teachers. My god, I couldn't stand mine. And the fact that my Digital Circuits Prof was a complete ***** didn't help either. I much prefer CS though. For some reason it just fits my mind better. Link to comment Share on other sites More sharing options...
haithman Posted April 3, 2009 Share Posted April 3, 2009 3rd-year Aerospace Engineering at Georgia Tech. Nice. I have a really good friend who goes to GT. I hear its intense Link to comment Share on other sites More sharing options...
Mooka Posted April 3, 2009 Share Posted April 3, 2009 What turned me away from engineering was HORRIBLE Physics teachers. My god, I couldn't stand mine. And the fact that my Digital Circuits Prof was a complete ***** didn't help either.I much prefer CS though. For some reason it just fits my mind better. My Physics teachers have all been very good. Its a fun subject.I'll admit the majority of EE profs aren't great. (that I've had anyway) Mainly, you learn by doing it yourself, and by your peers. I have 2 that I can hardly understand. I mean literally, they are very difficult to understand. Listening to one of them go though 00 01 10 11 is painful. Link to comment Share on other sites More sharing options...
Slacky McSlackAss Posted April 3, 2009 Share Posted April 3, 2009 My Physics teachers have all been very good. Its a fun subject.I'll admit the majority of EE profs aren't great. (that I've had anyway) Mainly, you learn by doing it yourself, and by your peers. I have 2 that I can hardly understand. I mean literally, they are very difficult to understand. Listening to one of them go though 00 01 10 11 is painful. It's all jeero's and vone's with me. Atleast I can understand an Indian accent. Link to comment Share on other sites More sharing options...
CRobi21 Posted April 3, 2009 Author Share Posted April 3, 2009 Easy.Just take your y-intercept coordinate you're given: (0, -6) x = 0 f(x) = -6 Plug it in. -6 = a(0-3)^2 + 3 -6 = a(9) + 3 9a = -9 a = -1 Then expand equation. f(x) = (-1)(x-3)^2 + 3 f(x) = (-1)(x^2 - 6x + 9) + 3 f(x) = -x^2 + 6x - 6 You da man!! Alright, this is for your eyes, and your eyes only. It's making it's ES debut. If you like me, you better put a ring on me. No one else watch this. Link to comment Share on other sites More sharing options...
Mooka Posted April 3, 2009 Share Posted April 3, 2009 It's all jeero's and vone's with me. Atleast I can understand an Indian accent. I have trouble with that. My main problem with Indian professors is their math backrounds are ridiculously strong. They breeze over it so fast, sometimes you get the concepts confused. Link to comment Share on other sites More sharing options...
SkinsMaster88 Posted April 3, 2009 Share Posted April 3, 2009 You da man!!Alright, this is for your eyes, and your eyes only. It's making it's ES debut. If you like me, you better put a ring on me. No one else watch this. :puke: :hysterical: You've got great dancing skills... Link to comment Share on other sites More sharing options...
SonOfWashington Posted April 3, 2009 Share Posted April 3, 2009 STB21, in this situation, your parabola is opening downward since you have a y-intercept lower than your vertex, so there will be a symmetrical point across the line x=3 at (6,-6) If you have a graphing calculator (I have a TI-83 Plus, so I'll use that), you can use it to figure it out this way: 1. Go to STAT > EDIT. 2. Enter your points (3,3), (0,-6), and as I mentioned above, (6,-6). 3. Hit STAT again, go right to CALC, choose QuadReg. 4. Hit enter twice and you have your solution. TO CHECK 1. Go to your y-editor (y=). Arrow up to highlight Plot 1, and hit enter. In the graph you should see the three points. 2. Plug in your quadratic equation and if it goes through the points, winner winner chicken dinner. If you don't have the TI-83 and want an on-screen one, PM me and I can email it to anyone who wants it. ~SOW Link to comment Share on other sites More sharing options...
Cherick Posted April 3, 2009 Share Posted April 3, 2009 I tried....... Link to comment Share on other sites More sharing options...
ixcuincle Posted April 3, 2009 Share Posted April 3, 2009 I'm just glad I quit math after Calc II. I've seen what's after Calc II and it's not pleasant. The worst thing about Math and Physics were the tests, you were given a three page test, there are like 5 problems. However each problem takes you like an hour to do lol... I had a good Physics teacher back in the day but neither him or the TA could explain the complicated workings of basic freshman physics. Once you bring in any of the 6 trig functions, I'm immediately lost. Same with logs and ln, they would scribble partial derivatives and logs on the white board and I had no idea what was going on. Link to comment Share on other sites More sharing options...
mjah Posted April 3, 2009 Share Posted April 3, 2009 Where do you go to school and what are you studying? Triple integrals were kind of annoying especially when you have to think in freaking 4 dimensions. They are even more annoying when trying to set up a probability problem Getting multiple integrals involved with probability problems was pretty much my favorite part of math, ever. Probability starts out so discrete, and then all of a sudden whooooaaaaBAM you're smearing it into distributions and finding a good everyday use for all that Calculus. So cool. Link to comment Share on other sites More sharing options...
CrypticVillain Posted December 17, 2012 Share Posted December 17, 2012 ES, the new homework center. llam.I would help you but I am done with math, FOREVER!!! When I see that I just blackout. I thought I was done with math forever, but I switched to IT and had to take two more math classes..... Anyway, I need help with these two questions Given the functionL y^2-x^3+4=0 Use implicit differentiation to find dy/dx and Evaluate dy/dx at the point (-2, 2) For the life of me, I cannot solve this dumb problem. Link to comment Share on other sites More sharing options...
S.T.real,lights,out Posted December 17, 2012 Share Posted December 17, 2012 Nevermind that isn't right.. http://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/implicitdiffdirectory/ImplicitDiff.html Maybe this would help... Link to comment Share on other sites More sharing options...
CrypticVillain Posted December 17, 2012 Share Posted December 17, 2012 The messed up part is that I took notes, some good notes too, and I still can't get this stupid question right. I hate math.... Link to comment Share on other sites More sharing options...
Corcaigh Posted December 17, 2012 Share Posted December 17, 2012 It's been > 25 years since I thought about this but isn't it as simple as: As they are asking you to use implicit differentiation, differentiate term by term Use the chain rule and create an equation for y' Substitute for x and y Link to comment Share on other sites More sharing options...
CrypticVillain Posted December 17, 2012 Share Posted December 17, 2012 It's been > 25 years since I thought about this but isn't it as simple as:As they are asking you to use implicit differentiation, differentiate term by term Use the chain rule and create an equation for y' Substitute for x and y I forgot about the chain rule. I am about to try it out now.. Link to comment Share on other sites More sharing options...
ixcuincle Posted December 17, 2012 Share Posted December 17, 2012 Link to comment Share on other sites More sharing options...
DCSaints_fan Posted December 17, 2012 Share Posted December 17, 2012 I thought I was done with math forever, but I switched to IT and had to take two more math classes.....Anyway, I need help with these two questions Given the functionL y^2-x^3+4=0 Use implicit differentiation to find dy/dx and Evaluate dy/dx at the point (-2, 2) For the life of me, I cannot solve this dumb problem. Differentiate the whole side with respect to x 1) d/dx (y^2 -x^3 + 4) = d/dx(0) 2) d/dx (y^2) - d/dx(x^3)+ d/dx(4) = 0 - Deriviate of sum is equal to the sum of the deriviatives 3) 2y(dy/dx) - 3x^2 + 0 = 4 - You use the chain rule on the first term, second term is just usual polynomial differentiation dy/dx = (4-3x^2)/2y Link to comment Share on other sites More sharing options...
ixcuincle Posted December 17, 2012 Share Posted December 17, 2012 Was rambling in chat about how if I ever returned to an elementary college physics, calculus, multivar, linear algebra, or differential equations course, I'd fail it...and I have over 9 years of college experience I would seriously struggle and I've been in college for over 9 years That's how hard that stuff is Link to comment Share on other sites More sharing options...
CrypticVillain Posted December 17, 2012 Share Posted December 17, 2012 It's been > 25 years since I thought about this but isn't it as simple as:As they are asking you to use implicit differentiation, differentiate term by term Use the chain rule and create an equation for y' Substitute for x and y Differentiate the whole side with respect to x1) d/dx (y^2 -x^3 + 4) = d/dx(0) 2) d/dx (y^2) - d/dx(x^3)+ d/dx(4) = 0 - Deriviate of sum is equal to the sum of the deriviatives 3) 2y(dy/dx) - 3x^2 + 0 = 4 - You use the chain rule on the first term, second term is just usual polynomial differentiation dy/dx = (4-3x^2)/2y Thanks. Once I remebered how to do the chain rule I was set.... Hopefully this time I am done with math for real. I can't take this stuff anymore... http://i.imgur.com/sVAzu.jpg I have seen everything now. Link to comment Share on other sites More sharing options...
CRobi21 Posted December 17, 2012 Author Share Posted December 17, 2012 Sick sig ML. I gotta get me one of those hats. Oh, and thanks for making me looks dumb again with the bump. Link to comment Share on other sites More sharing options...
HoggLife Posted December 18, 2012 Share Posted December 18, 2012 If it is multiple choice choose Your welcome. I'm arouse when I say it took me 2 seconds in that answer. Link to comment Share on other sites More sharing options...
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