CRobi21 Posted April 3, 2009 Share Posted April 3, 2009 Ok, I know this really isn't that hard. But I've been doing frickin math problems all day, and can't find it in myself to do this one. The vertex is (3,3). The y-intercept is (0,-6). Answer needs to be in f(x)= ax^2 + bx +c form. First one who gets it will receive something special from yours truly. Link to comment Share on other sites More sharing options...
CrypticVillain Posted April 3, 2009 Share Posted April 3, 2009 ES, the new homework center. llam. I would help you but I am done with math, FOREVER!!! When I see that I just blackout. Link to comment Share on other sites More sharing options...
ixcuincle Posted April 3, 2009 Share Posted April 3, 2009 What's a vertex? I helped the last time someone had one of those math questions, but this is the quadratic graphing ****. If it's not a straight line, I have no clue how to graph fancy-schmancy functions. Someone else more trained in quadratics has to do this. Link to comment Share on other sites More sharing options...
Mondizzle Posted April 3, 2009 Share Posted April 3, 2009 How many people are gonna come in here, get embarrassed, then leave in shame? Just me? Okay :doh: Link to comment Share on other sites More sharing options...
TheGoodBits Posted April 3, 2009 Share Posted April 3, 2009 Haha I haven't had a math class since I passed calculus last year... now I take out my calculator for anything. Anything with letters in it, don't ask me.:cool2: Link to comment Share on other sites More sharing options...
CRobi21 Posted April 3, 2009 Author Share Posted April 3, 2009 What's a vertex? There's a graph with it too. But I can't post it. It's like a curved line that is opening upwards, and the vertex is the point at which the curved line comes to it's peak. Like that, but only one line. Link to comment Share on other sites More sharing options...
ixcuincle Posted April 3, 2009 Share Posted April 3, 2009 Hopefully this helps. There's a bunch of junk that I can no longer explain, because I haven't done this **** in over 7 or 8 years. When I did do it I got a C because I didn't understand a word of this. http://en.wikipedia.org/wiki/Quadratic_function Good luck. Link to comment Share on other sites More sharing options...
Slacky McSlackAss Posted April 3, 2009 Share Posted April 3, 2009 c is equal to -6. I could solve it if I had one more equation. Link to comment Share on other sites More sharing options...
CRobi21 Posted April 3, 2009 Author Share Posted April 3, 2009 I hate my teacher. She'll do the simplest version of these problems, then expect us to do ones with like 9 and 10 steps to solve it. I'm bout to burn down her house. Link to comment Share on other sites More sharing options...
CRobi21 Posted April 3, 2009 Author Share Posted April 3, 2009 Ok, here's some help. f(x) = a(x-h)^2 + k Where (h,k) is the vertex. Link to comment Share on other sites More sharing options...
ixcuincle Posted April 3, 2009 Share Posted April 3, 2009 f(x) = a(x-3)^2 + 3 What the heck is "a"? Dumb vague variable. I would assume one of the numbers from the y-intercept needs to be plugged in. Then you find y, x, and then go for A. Then you fill all that mumbo jumbo into the top equation in OP except for X and Y. That sounds like a solution. Too lazy to do that so see what happens. This is basic high school math and I'm struggling with this Link to comment Share on other sites More sharing options...
difleha Posted April 3, 2009 Share Posted April 3, 2009 I don't know...I'm still taking Calculus 1 though. EDIT: Okay, you're gonna have to find standard form for y = a(x-3)^2 + 3. I would take away the a just to make it a little clearer. Link to comment Share on other sites More sharing options...
CRobi21 Posted April 3, 2009 Author Share Posted April 3, 2009 First one who gets it will receive something special from yours truly. I mean I posted that and figured people would bust their *** to try and figure it out. I guess not. I guess no one wants that special suprise. Link to comment Share on other sites More sharing options...
ixcuincle Posted April 3, 2009 Share Posted April 3, 2009 Can't you just plug those two numbers into your TI-83+ and use QuadReg or something? One of you who has had training with the graphing calculator, back me up on this http://www.prenhall.com/divisions/esm/app/calculator/medialib/Technology/Documents/TI-83/desc_pages/quad-reg.html Edit : QuadReg keeps getting error. I'm guessing the two coordinates given are not enough to graph a parabola. I give up. Link to comment Share on other sites More sharing options...
DCSaints_fan Posted April 3, 2009 Share Posted April 3, 2009 Since you're given the vertex, you should be able to figure out one more point from the y-intercept, because parabolas are symmetric. (Hint: What will the x-value be when y is -6, on the other side of the parabola? ) Now you have three equations, and three free variables, which you should be able to solve. Link to comment Share on other sites More sharing options...
SkinsMaster88 Posted April 3, 2009 Share Posted April 3, 2009 Ok, here's some help.f(x) = a(x-h)^2 + k Where (h,k) is the vertex. Easy. Just take your y-intercept coordinate you're given: (0, -6) x = 0 f(x) = -6 Plug it in. -6 = a(0-3)^2 + 3 -6 = a(9) + 3 9a = -9 a = -1 Then expand equation. f(x) = (-1)(x-3)^2 + 3 f(x) = (-1)(x^2 - 6x + 9) + 3 f(x) = -x^2 + 6x - 6 Link to comment Share on other sites More sharing options...
Slacky McSlackAss Posted April 3, 2009 Share Posted April 3, 2009 I get 1/3 credit for telling you that c is -6 Link to comment Share on other sites More sharing options...
SkinsMaster88 Posted April 3, 2009 Share Posted April 3, 2009 Man I wish the problem sets I get were this easy. Everything does seem easier than 'rocket science', especially at one of the toughest colleges in the country. Try combining differential equations, triple integrals, eigenvalues, and physics equilibrium equations in problems taking over 2-3 pages per each part. I hate the 6-8 hr problem sets I have to do. Link to comment Share on other sites More sharing options...
Slacky McSlackAss Posted April 3, 2009 Share Posted April 3, 2009 Man I wish the problem sets I get were this easy. Everything does seem easier than 'rocket science', especially at one of the toughest colleges in the country. Try combining differential equations, triple integrals, eigenvalues, and physics equilibrium equations in problems taking over 2-3 pages per each part.I hate the 6-8 hr problem sets I have to do. I like Differential Equations. Easily one of my favorite classes. But it helps to have a really good professor. Link to comment Share on other sites More sharing options...
SkinsMaster88 Posted April 3, 2009 Share Posted April 3, 2009 Diff Eq is fine. It's just a matter of some time-consuming problems afterwards in engineering. Link to comment Share on other sites More sharing options...
Slacky McSlackAss Posted April 3, 2009 Share Posted April 3, 2009 Diff Eq is fine. It's just a matter of some time-consuming problems afterwards in engineering. And THAT'S why I switched to Computer Science. Link to comment Share on other sites More sharing options...
Mooka Posted April 3, 2009 Share Posted April 3, 2009 I like Differential Equations. Easily one of my favorite classes. But it helps to have a really good professor. Man, if you have a good DE professor your math life will always be a thousand times easier. Plus its really hard to find a good textbook. Mine was excellent and I took that class in the summer at a JC. Its made my engineering life so much easier. And THAT'S why I switched to Computer Science. Computer science is the DEBIL! Hours and hours of debugging for a mistake you'll never find. Though I've been told that I need much more software experience in todays job market. Bleh. Link to comment Share on other sites More sharing options...
haithman Posted April 3, 2009 Share Posted April 3, 2009 Man I wish the problem sets I get were this easy. Everything does seem easier than 'rocket science', especially at one of the toughest colleges in the country. Try combining differential equations, triple integrals, eigenvalues, and physics equilibrium equations in problems taking over 2-3 pages per each part.I hate the 6-8 hr problem sets I have to do. Where do you go to school and what are you studying? Triple integrals were kind of annoying especially when you have to think in freaking 4 dimensions. They are even more annoying when trying to set up a probability problem Link to comment Share on other sites More sharing options...
SkinsKin26 Posted April 3, 2009 Share Posted April 3, 2009 I got to the party late and missed all of the fun. Link to comment Share on other sites More sharing options...
SkinsMaster88 Posted April 3, 2009 Share Posted April 3, 2009 Where do you go to school and what are you studying? Triple integrals were kind of annoying especially when you have to think in freaking 4 dimensions. They are even more annoying when trying to set up a probability problem 3rd-year Aerospace Engineering at Georgia Tech. Link to comment Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.