SUSkinsFan Posted October 12, 2008 Share Posted October 12, 2008 One of the officers at work just gave me a puzzle to try and solve and I need some help. A door has a unique 6 digit code. The final digit is 8 Odd and Even digits alternate (0 is even) The difference between two adjacent digits is bigger than 1 Now here's the kicker: "The 1st two digits (read as 1 number), as well as the middle two digits (read as 1 number), are multiples of the last two digits (read as 1 number)" If anyone can help me out I'd appreciate it. Link to comment Share on other sites More sharing options...
stupidmorals Posted October 12, 2008 Share Posted October 12, 2008 Do you want hints, or do you want the answer? Answer: 9 0 3 6 1 8 Link to comment Share on other sites More sharing options...
SUSkinsFan Posted October 12, 2008 Author Share Posted October 12, 2008 Do you want hints, or do you want the answer?I see what I was doing wrong...thanks Link to comment Share on other sites More sharing options...
stupidmorals Posted October 12, 2008 Share Posted October 12, 2008 I see what I was doing wrong...thanks Okay, PM me if you get stuck. Link to comment Share on other sites More sharing options...
SUSkinsFan Posted October 12, 2008 Author Share Posted October 12, 2008 Okay, PM me if you get stuck.I accidentally saw the ninja answer when I quoted your original post. Once I saw it though I realized what I had been doing wrong. Link to comment Share on other sites More sharing options...
Larry Posted October 12, 2008 Share Posted October 12, 2008 I'm coming up with multiple solutions. Link to comment Share on other sites More sharing options...
dfitzo53 Posted October 12, 2008 Share Posted October 12, 2008 I'm coming up with multiple solutions. I only count one that follows all the rules. Incidentally, I think one of the rules is actually superfluous. Edit: Nevermind, you need all the rules. Link to comment Share on other sites More sharing options...
Larry Posted October 13, 2008 Share Posted October 13, 2008 Ah, you're right. (I was observing that 90 is a multiple of 18, but 90 violates the adjacent-number rule by itself.) Link to comment Share on other sites More sharing options...
stupidmorals Posted October 13, 2008 Share Posted October 13, 2008 I accidentally saw the ninja answer when I quoted your original post. Once I saw it though I realized what I had been doing wrong. Dang, sorry about that, I didn't mean to give it away. Link to comment Share on other sites More sharing options...
Ancalagon the Black Posted October 13, 2008 Share Posted October 13, 2008 Ah, you're right. (I was observing that 90 is a multiple of 18, but 90 violates the adjacent-number rule by itself.) No, it doesn't. Check your solution - chances are (if it doesn't involve 90) there's something amiss. Link to comment Share on other sites More sharing options...
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